\left( a + b \right)^{2} = a^{2} + b^{2} + 2ab

\left( a + b \right)^{2} = a^{2} + b^{2} + 2ab

$latex \left( a + b \right)^{2} = a^{2} + b^{2} + 2ab $

Wrong shortcode initialized

( T = \frac{1}{f} ) period (in seconds)

$$
\begin{align} y = A \cos(kx – \omega t) && y = A \sin(kx – \omega t) \end{align}
$$

$$a^{2}+b^{2}=(a+b)^{2}-2ab$$